The exams of the railway have started and RRB has notified about some changes that have been made to the method of the normalization of the marks. The method of normalization formula is the implementation in those examinations that occurs in more than one shift.
It is a statistic based rule, which takes into account the examination’s various shift paper’s level of difficulty. The examination of railways including NTPC, Gr.-D, and examinations for other posts will also occur in many sessions as the number of applied candidates is almost 2.5 crores.
In the computer-based exam’s 1st stage, in the 2nd stage of the computer-based exam for some seventh CPC levels and also for various other tests, the exams might be conducted in more than one session. For these exams that occur in more than one session, on the basis of the level of difficulty of various papers a suitable method for normalization is used.
For the normalization process, the raw marks (actual marks) of the examinee, the average of the marks that have been scored by the top 0.1 percent examinees of all the shifts, the sum of average and S.D. marks of the examinees in all the sessions, the average of the marks that have been scored by the top 0.1 percent examinees of the shift in which the examinee had given exam, the sum of average and S.D. marks of the examinees in the session in which the examinee had given the exam and the sum of average marks of examinees in the shift which have maximum average and S.D. of marks of examinees among all the shifts, are considered.
Railway Recruitment Board had notified earlier that if the total number of the candidates who gave the exam in a particular shift will be less than 1 thousand, the marks of the candidate who will be the topper of that shift will be considered in place of the mean marks of the top 0.1 percent candidates. This particular rule has now been changed.
A new parameter has been added by the railways for the method of normalisation of the marks.
For normalizing the marks of the examinees, the sum of average marks of the examinees in that particular shift which have the maximum mean and S.D. of the marks of the examinees in the exam among all the shifts.
The calculation of the marks will be done up to five places of the decimal.
The calculation of raw marks of the candidates will be done in the following way-
Suppose the candidates have attempted 60 questions out of 100 questions, among which they have answered 51 questions correctly and the remaining 9 answers incorrectly.
Then, the candidates will get negative marks for these 9 wrong answers, and marks of 3 correct answers will also be deducted, as the negative marks for an incorrect answer is one-third marks. Thus, they will get marks for 48 correct answers only.